The coefficient of in the expansion of is ______________
Given: (1/a – 2b/3)10
Thus, Tr+1 = 10Cr(1/a)10-r (-2b/3)r
Now, for the coefficient of a-6b4,
10 – r = 6
Thus, r = 4
Therefore the coefficient of a-6b4 = 10C4(-2/3)4
= 10.9.8.7.6!/6!.4.3.2.1 . 24/34
= 1120/27