For the reaction H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g) the standard free energy is \Delta G^{\circleddash }>0. The equilibrium constant (K) would be,

(i) K = 0

(ii) K > l

(iii) K = 1

(iv) K < 1

Answers (1)

The answer is the option (iv) K < 1

Explanation: As \Delta G^{\Theta }=-RT lnK and so if \Delta G^{\Theta }>0, then -\Delta G^{\Theta }/RT is negative, which means K<1. This certainly implies that a non-spontaneous reaction or a reaction proceeds in the forward direction to such a small degree that only a very small quantity of product is formed.

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