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Q.5 How many elements has P(A), if A = \phi?

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Let the elements in set A be m,then n\left ( A \right ) = m

then, number of elements in power set of A         n\left ( p\left ( A \right )\right ) = 2^{m}

Here,  A = \phi   so    n\left ( A \right ) = 0

n\left [ P\left ( A \right ) \right ] = 2^{0} =1

Hence,we conclude P(A) has 1 element.

Posted by

Safeer PP

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