5.    If \sec 4A= cosec (A-20^{o}), where 4A is an acute angle, find the value of A.

Answers (1)
M manish

We have,
\sec 4A= cosec (A-20^{o}), Here 4A is an acute angle
According to question,
We know that  cosec(90^0-\theta)= \sec \theta
cosec(90^0-4A)= cosec (A-20^{o})

\\\Rightarrow 90 - 4A = A - 20\\\\ \Rightarrow 5A=110\\\\ \Rightarrow A=\frac{110}{5}\\\:\\ \Rightarrow A=22^o

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