Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • If sec 4A = to cosec A - 20^o where 4A is an acute angle find the value of A.

5.    If \sec 4A= cosec (A-20^{o}), where 4A is an acute angle, find the value of A.

Answers (1)

best_answer

We have,
\sec 4A= cosec (A-20^{o}), Here 4A is an acute angle
According to question,
We know that  cosec(90^0-\theta)= \sec \theta
cosec(90^0-4A)= cosec (A-20^{o})

\\\Rightarrow 90 - 4A = A - 20\\\\ \Rightarrow 5A=110\\\\ \Rightarrow A=\frac{110}{5}\\\:\\ \Rightarrow A=22^o

Posted by

manish

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE opens post-result facilities for Class 10 main, 2nd exams 2026; apply for scanned copies by August 9

Latest Question