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  • If tan A= cot B, prove that A+ B = 90^o.

4.    If \tan A= \cot B, prove that A+B= 90^{o}.

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best_answer

We have,
\tan A= \cot B
and we know that \tan (90^0 - \theta)= \cot \theta
therefore, 
\tan A= \tan(90^0- B)
A = 90 - B 
A + B = 90
Hence proved.

Posted by

manish

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