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7. In a right triangle $ABC,$ $\angle B=90^{\circ}$

(a) If $AB=6cm$ , $BC=8cm$ , find $AC$

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Using Pythagoras theorem,

$AC^2 = AB^2 + BC^2 = 6^2 + 8^2 = 100$

By prime factorisation of 100 :- $2\times2\times5\times5$

We get, AC = 10cm

Posted by

Devendra Khairwa

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