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  • In Fig, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the

12. In Fig, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the

(i) Quadrant OACB

 

Answers (1)

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The quadrant OACB is a sector with an angle of 90o and a radius of 3.5 cm.

Thus the area of the quadrant is:- 

 =\ \frac{90^{\circ}}{360^{\circ}}\times \pi \times 3.5^2

=\ \frac{77}{8}\ cm^2

Hence the area of the quadrant is    \frac{77}{8}\ cm^2   .

Posted by

Devendra Khairwa

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