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Q4  In Fig. 6.19, DE || AC and DF || AE. Prove that BF / FE = BE / EC

  

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Given :  DE || AC and DF || AE.

To prove : 

                  \frac{BF}{FE} = \frac{BE}{EC }

Since , DE || AC so we have 

\frac{BD}{DA}=\frac{BE}{EC}.............................................1

Also,DF || AE

\frac{BD}{DA}=\frac{BF}{FE}.............................................2

 

From equation 1 and 2, we have 

\frac{BF}{FE} = \frac{BE}{EC }

Hence proved 

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seema garhwal

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