Q

# In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP similar to triangle ADB

Q7 (3)   In Fig. 6.38, altitudes AD and CE of $\Delta ABC$ intersect each other at the point P. Show that:

$\Delta AEP \sim \Delta ADB$

Views

To prove : $\Delta AEP \sim \Delta ADB$

In $\Delta AEP \, \, \, and\, \, \Delta ADB$,

$\angle AEP=\angle ADB$     ( Both angles are right angle)

$\angle A=\angle A$        (Common )

$\Delta AEP \sim \Delta ADB$    ( By AA criterion)

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