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In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP similar to triangle ADB

Q7 (3)   In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that:

             \Delta AEP \sim \Delta ADB 

             

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To prove : \Delta AEP \sim \Delta ADB

In \Delta AEP \, \, \, and\, \, \Delta ADB,

        \angle AEP=\angle ADB     ( Both angles are right angle)

     \angle A=\angle A        (Common )

\Delta AEP \sim \Delta ADB    ( By AA criterion)

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