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  • In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP is similar to triangle CDP

Q7 In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that:

 \Delta AEP \sim \Delta CDP

  

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To prove : \Delta AEP \sim \Delta CDP

In \Delta AEP \, \, and\, \, \Delta CDP,

\angle AEP=\angle CDP     ( Both angles are right angle)

\angle APE=\angle CPD     (Vertically opposite angles )

\Delta AEP \sim \Delta CDP    ( By AA criterion)

 

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seema garhwal

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