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Q7 In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that :    

     

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Join BC

In \triangle APC\, \, and\, \triangle DPB,

\angle APC\, \, = \angle DPB      ( vertically opposite angle)

\angle CAP\, \, = \angle BDP      (Angles in the same segment)

\triangle APC\, \, \sim \triangle DPB      (By AA)

\frac{AP}{DP}=\frac{PC}{PB}=\frac{CA}{BD}       (Corresponding sides of similar triangles are proportional)

\Rightarrow \frac{AP}{DP}=\frac{PC}{PB}

\Rightarrow AP.PB=PC.DP

 

 

 

 

 

Posted by

seema garhwal

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