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Q : 3     In the following APs, find the missing terms in the boxes :

           (i)  \small 2,\hspace {1mm}\fbox{ },\hspace {1mm} 26

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Given AP series is
\small 2,\hspace {1mm}\fbox{ },\hspace {1mm} 26
Here, a = 2 , n = 3 \ and \ a_3 = 26
Now, we know that
a_n = a+(n-1)d
\Rightarrow a_3 =2+(3-1)d
\Rightarrow 26 -2=(2)d
\Rightarrow d = \frac{24}{2}= 12
Now,
a_2= a_1+d
a_2= 2+12 = 14
Therefore, the missing term is 14

Posted by

Gautam harsolia

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