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  • In the previous problem (5.3), the magnitude of the momentum transferred during the hit is (a) Zero

In the previous problem (5.3), the magnitude of the momentum transferred during the hit is
(a) Zero
(b) 0.75 kg m s^{-1}
(c) 1.5 kg m s^{-1}
(d) 14 kg m s^{-1}

Answers (1)

The answer is the option (c) 1.5 kg m s^{-1}

Explanation: Change in momentum (\Delta \overrightarrow{p}) = Final momentum – initial momentum

(\Delta \overrightarrow{p})=-[ 0.9\widehat{i}+1.2\widehat{j} ]

Thus, its magnitude will be,

\left |\Delta \overrightarrow{p} \right |=\sqrt{(0.9)^{2}+(1.2)^{2}}

\left |\Delta \overrightarrow{p} \right |=\sqrt{0.81+1.44}

 \left |\Delta \overrightarrow{p} \right |=\sqrt{2.25}=1.5kgms^{-1}

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