Ka for CH_{3}COOH is 1.8\times 10^{-5}  and K_{b} , for NH_{4}OH is 1.8\times 10^{-5} . The pH of ammonium acetate will be

(i) 7.005

(ii) 4.75

 (iii) 7.0

(iv) Between 6 and 7

Answers (1)

The answer is the option (iii) 7.0

Explanation: The formation of ammonium acetate is formed by a weak base NH_{4}OH \; and \; CH_{3}COOH.

We know that in case of salts with weak acids,

pH = \frac{1}{2} [pKw + pKa - pKb ]

In this case,

= \frac{1}{2} [14 - log (1.8 \times 10-5) + log (1.8 \times 10-5 )]

=7

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