Q : 1         Multiply the binomials. 

                (ii) \small (y-8)  and \small (3y-4)

Answers (1)

We need to multiply (y - 8) and (3y - 4)
(y - 8) X  (3y - 4)  =   (y)(3y) +  (y)(-4) + (-8)(3y) + (-8)(-4)
                             =   3y^{2} - 4y - 24y  + 32
                              = 3y^{2} - 28y + 32

 

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