# pH of 0.08 mol dm-3  solution is 2.85. Calculate its ionisation constant.

As per the information given in the question, C =0.08 mol dm-3 and pH =2.85

We know that the HOCl is a weak acid, therefore its dissociation will be written as-

pH = -log [H+]

Thus, -2.85 = log [H+]

[H+] = antilog (-2.85)

[H+] = 1.41 × 10-3

We are aware that in case of a weak mono basic acid-

(squaring both sides)

Thus,

Therefore, we can conclude that the ionization constant of will be

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