Q : 3    Simplify. 

           (iv)(a+b)(c-d)+(a-b)(c+d)+2 (ac+bd)

Answers (1)

(a + b) X ( c -d) + (a - b) X (c + d) + 2(ac + bd )  
=   (a)(c) + (a)(-d) + (b)(c) + (b)(-d) +   (a)(c) + (a)(d) + (-b)(c) + (-b)(d)  + 2(ac + bd )
= ac - ad + bc - bd + ac +ad -bc - bd   + 2(ac + bd )
=  2(ac - bd )  + 2(ac +bd )
=  2ac - 2bd + 2ac  + 2bd 
= 4ac

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