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  • Subtract: 3l (l – 4 m + 5 n) from 4l ( 10 n – 3 m + 2 l )

Q : 5    (c)    Subtract: \small 3l(l-4m+5n)  from  \small 4l(10n-3m+2l)

Answers (1)

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At first we will solve each bracket individually,

                  \small 3l(l-4m+5n) = 3l^2 - 12lm + 15ln

and            \small 4l(10n-3m+2l) = 40ln - 12ml + 8l^2

Subtracting:

                   \small 40ln - 12ml + 8l^2 - (3l^2 - 12lm+15ln)

or                 \small = 40ln - 12ml + 8l^2 - 3l^2 + 12lm-15ln

or                 \small = 25ln + 5l^2

Posted by

Devendra Khairwa

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