# The enthalpy of vapourisation of   is 30.5 kJ mol–1 . Calculate the heat required for the vapourisation of 284 g of  at constant pressure. (Molar mass of  = 154 g mol–1).

As per the information provided in the question, for one mole of , the heat of vaporisation required is 30.5 kJ/mol .

Hence for the vaporisation of 284 g of , we require:

$= \frac{284 \; g}{154 \; g \; mol^{-1}} \times 30.5\; kJ\; mol^{-1}$

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