The enthalpy of vapourisation of  CCl_{4} is 30.5 kJ mol–1 . Calculate the heat required for the vapourisation of 284 g of CCl_{4} at constant pressure. (Molar mass of CCl_{4} = 154 g mol–1).

Answers (1)

As per the information provided in the question, for one mole of CCl_{4} (154 g), the heat of vaporisation required is 30.5 kJ/mol .

Hence for the vaporisation of 284 g of CCl_{4}, we require:

= \frac{284 \; g}{154 \; g \; mol^{-1}} \times 30.5\; kJ\; mol^{-1}

=56.2\; kJ

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