# The entropy change can be calculated by using the expression . When water freezes in a glass beaker, choose the correct statement amongst the following : (i) $\Delta S$ (system) decreases, but $\Delta S$ (surroundings) remains the same. (ii) $\Delta S$ (system) increases but $\Delta S$ (surroundings) decreases. (iii) $\Delta S$ (system) decreases, but $\Delta S$ (surroundings) increases. (iv) $\Delta S$ (system) decreases, and $\Delta S$ (surroundings) also decreases.

The answer is option (iii)  (system) decreases, but  (surroundings) increases.

Explanation: As we all know in the case of an exothermic process, heat is released, which leads to a decrease in the surrounding entropy and as a result, the system entropy increases. As freezing is an exothermic process, we choose this option.

## Most Viewed Questions

### Preparation Products

##### Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-
##### Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
##### NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-
##### NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-