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  • The graph between two temperature scales A and B is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal division on scale A and 100 on scale B. The relationship for conversion between the two scales is given by

The graph between two temperature scales A and B is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal division on scale A and 100 on scale B. The relationship for conversion between the two scales is given by

a) \frac{t_{A}-180}{100}=\frac{t_{B}}{150}

b) \frac{t_{A}-30}{150}=\frac{t_{B}}{100} 

c) \frac{t_{B}-180}{150}=\frac{t_{A}}{150}

d) \frac{t_{B}-40}{100}=\frac{t_{A}}{180}

 

Answers (1)

The answer is the option b) \frac{t_{A}-30}{150}=\frac{t_{B}}{100}

Explanation: Now, from graph tA, we know that,

Lower fixed point (LFP) = 30^{\circ}

& upper fixed point (UFP) = 180^{\circ}

Similarly, in case of scale B,

UFP = 100^{\circ}

& LFP = 0^{\circ}

Thus, the formula,

\frac{t_{A}-(LFP)}{(UFP)_{A}-(LFP)_{A}}= \frac{t_{B}-(LFP)_{B}}{(UFP)_{B}-(LFP)_{B}} 

\frac{T_{A}-30}{180-30}= \frac{t_{B}-0}{100-0 } or \frac{ t_{A}-30}{150}= \frac{t_{B}}{100 }

Posted by

infoexpert24

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