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  • The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen? (i) 0.8 \times 10^{5} atm (ii) 0.008\; Nm^{-2} (iii) 8\times 10^{4}Nm^{-2} (iv) 0.25\; atm

The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?
(i) 0.8 \times 10^{5} atm
(ii) 0.008\; Nm^{-2}
(iii) 8\times 10^{4}Nm^{-2}
(iv) 0.25\; atm

Answers (1)

We know that,

The partial pressure of O2 = Mole fraction of O2 × total pressure of the mixture

=\frac{4}{5}\times 1\; atm=0.8\; atm

=0.8\times 10^{5}Nm^{-2}=8\times 10^{4}Nm^{-2}

Hence option (iii) is correct 

 

                

Posted by

infoexpert22

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