Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The value of tan 3A – tan 2A –tan A is equal to A. tan 3A tan 2A tan A B. – tan 3A tan 2A tan A C. tan A tan 2A – tan 2A tan 3A – tan 3A tan A D. None of these

The value of \tan 3A - \tan 2A -\tan A is equal to

A. \tan 3A \tan 2A \tan A

B. - \tan 3A \tan 2A \tan A

C. \tan A \tan 2A - \tan 2A \tan 3A - \tan 3A \tan A

D. None of these

Answers (1)

The answer is the option (a).  


 \\ \tan 3A=\tan \left( 2A+A \right) =\frac{\tan 2A+\tan A}{1 - \tan 2A\tan A} \\\\ \tan 3A \left( 1 - \tan 2A\tan A \right) =\tan 2A+\tan A \\\\ \tan 3A - \tan 3A\tan 2A\tan A=\tan 2A+\tan A \\\\ \tan 3A\tan 2A\tan A=\tan 3A - \tan 2A - \tan A \\\\

Hence, a is correct.

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question