Three immiscible liquids of densities   and refractive indices 
  are put in a beaker. The height of each liquid column is 
. A dot is made at the bottom of the beaker. For near normal vision, find the apparent depth of the dot.
Key concept : Coordinate convention: At the first surface (+upward and -ve downward)
 (infinity because the surface is plane)
or  The negative sign shows that it is on the side of the object
 is the apparent depth of O after refraction from interface.
The position of image O after the refraction from surface-1. If seen from , the apparent depth is 
 
The negative sign indicates that it is on the side of the object.
Since the image formed by surface-1. It will act as an object for surface-2. If seen from  , the apparent depth is 
 .
Similarly, the image formed by medium 2,  acts as an object for medium 3
Finally the image formed by surface -2 will act as an object for surface-2. If seen from outside, the apparent depth is 
Hence apparent depth of odt is 
Important point:
Apparent depth (distance of final image from final surface)