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  • Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have new combination of characters.

Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have new combination of characters. Choose the new combination from the following
(i) Round, yellow 
(ii) Round, green 
(iii) Wrinkled, yellow 
(iv) Wrinkled, green 

(a) (i) and (ii)

(b) (i) and (iv) 

(c) (ii) and (iii)

(d) (i) and (iii) 

Answers (1)

Answer: (b)

Solution:
Here a typical dihybrid cross is given.
Two characters are considered at a time:

  1. Colour of the seeds (green or yellow)
  2. Shape of the seeds (round or wrinkled).

When F1 plants are selfed in a typical dihybrid cross, we get two parental combinations in the ratio 9:3:3:1.
So the phenotypic ratio of 9: 3: 3: 1 is obtained.
Round Yellow: Round green: Wrinkled yellow: Wrinkled green = 9:3:3: 1 The two new combinations are round & yellow seeds and wrinkled & green seeds are

Therefore, option (b) is correct.

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infoexpert26

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