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Q : 7 Using $a^2-b^2=(a+b)(a-b)$ , find

(ii) $(1.02)^2-(0.98)^2$

Answers (1)

best_answer

We know,

$a^2-b^2=(a+b)(a-b)$

Using this formula,

$(1.02)^2-(0.98)^2$ = (1.02 + 0.98)(1.02 - 0.98)
= (2.00)(0.04)

= 0.08

Posted by

HARSH KANKARIA

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