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Q : 7        Using   a^2-b^2=(a+b)(a-b) ,  find

              (ii) (1.02)^2-(0.98)^2

Answers (1)

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We know,

a^2-b^2=(a+b)(a-b)

Using this formula,

(1.02)^2-(0.98)^2 = (1.02 + 0.98)(1.02 - 0.98)
= (2.00)(0.04)

= 0.08

Posted by

HARSH KANKARIA

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