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Q.1 Which of the following numbers are not perfect cubes?

(ii) 128

Answers (1)

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We have 128.  By prime factorization we get,

         128 = 2\times2\times2\times2\times2\times2\times2

Since the prime numbers are not in pairs of three, so the given number is not a perfect cube.

Posted by

Devendra Khairwa

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