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Which of the following would weigh the highest?
(a) 0.2 mole of sucrose (C_{12} H_{22} O_{11})
(b) 2 moles of CO_{2}
(c) 2 moles of CaCO_{3}
(d) 10 moles of H_{2}O

Answers (1)

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Answer: C

Solution.
From mole concept, 
1 mole = molecular weight in gram. 
Weight of a sample in gram = Number of moles × Molar mass
Mass of 1 mole of sucrose (12 \times 12) + (1 \times 22) + (16 \times 11) = 342 g
Mass of 1 mole of CO_{2} = 12 + (16 \times 2) = 44g

Mass of 1 mole of CaCO_{3} = 40 + 12 + (16 \times 3) = 100g
Mass of 1 mole of H_{2}O = 2 + 16 = 18g
(a) 0.2 moles of C_{12} H_{22} O_{11} = 0.2 \times 342 = 68.4 g
(b) 2 moles of CO_{2} is 2 \times 44 = 88 g
(c) 2 moles of CaCO_{3} = 2 \times 100 = 200 g

(d) 10 moles of H_{2}O = 10 \times 18 = 180 g

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