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Would the Bohr formula for the H-atom remain unchanged if proton had a charge (+4/3) e and electron a charge (−3/4) e, where e = 1.6 × 10–19C. Give reasons for your answer.

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Neil Bohr proposed that if an electron is moving around a stationary nucleus, the require centripetal force is provided by the electrostatic force of attraction.

i.e \frac{1}{4 \pi \epsilon _{0}}\frac{q_{1}q_{2}}{r^{2}}=\frac{mv^{2}}{r} ...............(i)

Therefore the magnitude of electrostatic force

F\propto q_{1}\times q_{2}

The Bohr’s formula for the H-atom remains unchanged if the charge on the proton is (+4/3)e whereas the charge carried by the electron is (-3/4)e. This is possible as the Bohr’s formula requires the product of the charges which remain constant for given values of charges.

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