Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Write the coefficient of x^{2} in each of the following (i) \frac{\pi}{6}x+x^{2}-1 (ii) 3x-5+0.x^{2} (iii) (x-1)(3x-4) (iv) (2x-5)(2x^{2}-3x+1)

Write the coefficient of x^{2} in each of the following

(i) \frac{\pi}{6}x+x^{2}-1

(ii) 3x-5+0.x^{2}

(iii) (x-1)(3x-4)

(iv) (2x-5)(2x^{2}-3x+1)

Answers (1)

(i) 1

(ii) 0

(iii) 3

(iv) -16

Solution

The value which is multiplied by x^{2} is its coefficient.

(i) \frac{\pi}{6}x+x^{2}-1=\left (\frac{\pi}{6} \right )x+(1)x^{2}-1

Here x^{2} is multiplied with 1.

Hence the coefficient of x^{2}is one.

(ii) 3x-5+0.x^{2}

Here x^{2} is multiplied with 0.

Hence the coefficient of x^{2}is 0.

(iii) (x-1)(3x-4)

3x^{2}-4x-3x+4\\ 3x^{2}-7x+4

Here x^{2} is multiplied with 3.

Hence the coefficient of x^{2} is 3.

(iv) (2x-5)(2x^{2}-3x+1)

4x^{3}-6x^{2}+2x-10x^{2}+15x-5\\ 4x^{3}-16x^{2}+17x-5           

Here x^{2} is multiplied with -16. 

Hence the coefficient of x^{2} is -16.

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question