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If bromine atom is available in the form of, say, two isotopes 7935Br (49.7%) and 8135 Br (50.3%), calculate the average atomic mass of bromine atom.

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Given,  two isotopes  _35^79	extrmBr(49.7^o/_o) and  _35^81	extrmBr(50.3^o/_o).

Average atomic mass:

=79	imesfrac49.7100+81	imesfrac50.3100

=frac3926.3100+frac4074.3100

=frac8000.6100

=80.006u.

Posted by

Deependra Verma

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