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  • 5000 J of work would is done to carry how much charge between two points having potential difference of 100 V?

5000 J of work would is done to carry how much charge between two points having potential difference of 100 V?

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\ extGiven, potential difference (V)=100 V$ \ Work done $( W )=5000 J$ \ Charge $( Q )=?$ \ We know that; $V=fracWQ$ \ Or, $Q=fracWV$ \ Or, $Q=frac5000 J100 V=50 C

Posted by

Deependra Verma

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Potential difference=100

Work=5000J

Charge= ?

V=W/Q

Q=W/V

5000/100

=50 C

 

 

 

 

Posted by

Vaishnavi

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