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Get Answers to all your Questions
a car travelling at a speed of 54km/h is brought to rest in 90 seconds .Find accelaration and distance travelled before coming to rest ?
Answers (1)
The speed of the car = 54 Km/h = 15 m/sec
given u=15m/s
v=0 (rest)
v=u+at
The acceleration
a=-u/t=-15/90 =-1/6 m/s2
or retardation = 1/6 m/s2
View full answer
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