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  • A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, what is the magnitude and direction of acceleration of the stone?

A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25 s, what is the magnitude and direction of acceleration of the stone?

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\ extLength of string =80 cm =0.8 m$ \ Frequency $v=frac1425 Hz$ \ Angular frequency $omega=2 pi v$ \ $=2 imes frac227 imes frac1425=frac8825 rad s ^-1$ \ Centripetal acceleration $a=omega^2 r$ \ $=left(frac8825 ight)^2 imes 0.8=9.91 m s ^-2

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Deependra Verma

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