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  • Certain force acting on a 20 kg mass changes its velocity from 5 m s–1 to 2 m s–1. Calculate the work done by the force.

Certain force acting on a 20 kg mass changes its velocity from 5 m s–1 to 2 m s–1. Calculate the work done by the force.

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Mass.m = 20 kg.

Initial velocity, u=5m/s

Final velocity, v=2m/s

Work done = change in K.E.

W = frac12m u^2 -frac12m v^2 = frac12m( u^2- v^2)

      = frac1220( 2^2- 5^2) = -210J 

The negative sign implies the retarding 

nature of the applied force.

Posted by

Deependra Verma

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