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  • Consider a piller of length 10 cm . if a worm climbs 2cm and falls 1cm every 5 minutes to reach its house on top. then how much time would it take to reach its home??????

Consider a piller of length 10 cm . if a worm climbs 2cm and falls 1cm every 5 minutes to reach its house on top. then how much time would it take to reach its home??????

Answers (1)

The worm climbs 2 cm and falls 1 cm in 5 minutes.
So it effectively climbs (2-1)=1cm in 5 minutes.

For the first 8cm, it will take (8×5) = 40 minutes

At the end of 40 minutes, it will be at 8 cm.

Then in another 5 minutes it will reach the top. Once it reaches the top, it won't fall again.
So the total time is 40+5=45 minutes

 

Posted by

Satyajeet Kumar

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