Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Differential Equation exercise 21.3 question 21 sub question (iv) maths

Explain solution RD Sharma class 12 chapter Differential Equation exercise 21.3 question 21 sub question (iv) maths

Answers (1)

Answer:

y=a x+b+\frac{1}{2 x}   is a solution of differential equation

Hint:

Differentiate the function.

Given:

y=a x+b+\frac{1}{2 x}  


Solution:

Differentiating on both sides with respect to x

\begin{aligned} &\frac{d y}{d x}=a+\frac{1}{2}\left(\frac{-1}{x^{2}}\right) \\\\ &\frac{d y}{d x}=a-\frac{1}{2 x^{2}} \end{aligned}                .................(i)

Differentiating equation (i)

\begin{aligned} &\frac{d^{2} y}{d x^{2}}=\frac{-1}{2}\left(\frac{-2}{x^{3}}\right) \\\\ &\frac{d^{2} y}{d x^{2}}=\frac{1}{x^{3}} \\\\ &x^{3} \frac{d^{2} y}{d x^{2}}=1 \end{aligned}

Hence the given function is the solution of differential equation.

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

‘Careers are at stake’: CBSE removes additional subject option for private students without prior notice
anam-khan

CBSE eases APAAR ID mandate for board exams 2026 over lack of parental consent, technical issues
anam-khan

CBSE Board 2026: Exam form submission for Class 10, 12 private students begins tomorrow

Latest Question