find the product of (x+3y)(x^2-3xy+9y^2) .

Answers (1)

solution:   we have ,

                  (x+3y)(x^2-3xy+9y^2)

               =    (x+3y)(x^2-x	imes3y+(3y)^2)

              =    left ( a+b 
ight )left ( a^2-ab+b^2 
ight ), where , a=x  and  b=3y

                  =       a^3+b^3

                  =     x^3+(3y)^3 =x^3+ 27y^3

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