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  • I have three children. The youngest is the same age as the first digit in my age, another is the same age as the second digit in my age, and the third is the same age as the sum of the two digits in my age. The total of our ages is 33. How old am I?

I have three children. The youngest is the same age as the first digit in my age, another is the same age as the second digit in my age, and the third is the same age as the sum of the two digits in my age. The total of our ages is 33. How old am I?

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eginarrayl extIf I was AB years of age (which is really 10 imes A+B,\ extmy youngest child would be A years old, another would be B years old and the third would be A + B.\ extThe total is therefore:\ (10 imes A+B)+A+B+(A+B)=33\ Rightarrow 10A+B+A+B+A+B=33\ Rightarrow 12A+3B=33\ extHere A could be 1 or 2 \ extWhen A = 1 \ extThen B = 7 \ extSO my age is 17 And age of three chidren will be 1 , 7 , 8 , that make me 9 year old when i have my first childeren , that is not possible .\ extSO\ extTake A = 2 \ extThen\ extB = 3\ extthat makes my age 23 , and age of my three children = 2 , 3 , 5 \ extSo my age = 23 years endarray

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Deependra Verma

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