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If the product of first 10 natural numbers is 2^a x 3^b x 5^c x 7^d then find a+b+c+d

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Prodcut of first natural numbers

1 x2x3x4x5x6x7x8x9x10 = 2x3x2x2x5x2x3x7x2x2x2x3x3x2x5

                                         = 28 x 34 x 52 x 71  = 2a x 3b x 5c x 7d

a = 8, b =4, c =2 , d=1

a + b +c +d = 8 + 4 + 2 + 1 = 15 

Posted by

Ravindra Pindel

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