Solve for x and y: 148x+231y=527 231x+148y=610

Answers (1)

$ Given : $ 148x+231y=527..(i) \\ 231x+148y=610....(ii)\\ $ Equation (i)$ \times 231 - 148 \times Equation (ii) \\ 34118x-34118 x + 53361y - 21904y =121737 - 90280\\ 31457 y = 31457 \\ y =1 \\ $ put value of y in equation (i)$\\ 148 x = 527 - 231\\ 148 x = 296 \\ x = 2

Hence the value of x= 2 and y =1.

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