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Two mirrors m and n are perpendicular to each other at O .Ray AB is incident to the mirror m at point B and reflected back in the direction BC which is again incident o the mirror n at point C Ray CD is the finally reflected ray.Prove that ray AB is parallel to Ray CD

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Mirror;m;and;n;are;perp ;to ;each;other.\*ecause;AB;is;incident;ray;and;CD ;is;reflected;ray.\*	herefore ;angle 1=angle2;and;angle3=angle4\* Now,;construct;EAperp m;and;ECperp n.\* 	herefore angle AEC=90^circ\*In;	riangle AEC,\*indent angle AEC+angle EAC+angle ACE=180^circ\*Rightarrow 90^circ+angle 2 +angle 3=180^circ\*Rightarrow angle 2 +angle 3=90^circ\*Now, ;multiply;it;by;2\*2	imes angle 2 +2	imes angle 3=180^circ\*Rightarrow angle BAC +angle ACD=180^circ\* ecause angle BAC and; angle ACD,;forms;a;pair;of;consecutive;interior;\*angles;and;are;supplementary;angles.\* 	herefore AB || CD,;Hence;proved.

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Deependra Verma

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