Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  •  A ball is dropped from a high-rise platform at   starting from rest. After

 A ball is dropped from a high-rise platform at \mathrm{t}=0  starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed  v. The two balls meet at  t=18 \mathrm{~s}. What is the value of v ? (Take g=10 \mathrm{~m} / \mathrm{s}^2 )

Option: 1

75\ \frac{m}{s}


Option: 2

80\ \frac{m}{s}


Option: 3

120\ \frac{m}{s}


Option: 4

None of the above.


Answers (1)

For ball 1:

  h=\frac{1}{2}gt^2

 = \frac{1}{2}\times10\times{18}^2=1620\ m

For ball 2: 

h=1620m,\ u=v,t=18-6=12s

Therefore,  h=ut+\frac{1}{2}gt^2

Or, 1620=12v+\frac{1}{2}\times10\times{12}^2

Or, 12v=900

Or, v=75\ \frac{m}{s}

Posted by

Ramraj Saini

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC to revise NEET UG 2025 round 2 allotment after seat data error; withdraws result
anam-khan

MCC NEET UG Counselling 2025: Over 2,400 get upgraded seats in round 2 final allotment
anam-khan

AP NEET Counselling 2025: Free exit from round 1 allotted college by September 21; 180 new MBBS seats added

Latest Question