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  • A ball is projected with a velocity , at an angle of <img alt="\mathrm{60^{\circ}}" src="/latex-image/?%5Cmathrm%7

A ball is projected with a velocity \mathrm{10ms^{-1}}, at an angle of \mathrm{60^{\circ}} with the vertical direction . It's speed at the highest point of its trajectory will be:

Option: 1

\mathrm{5\sqrt{3}ms^{-1}}


Option: 2

\mathrm{5ms^{-1}}


Option: 3

\mathrm{10ms^{-1}}


Option: 4

Zero


Answers (1)

best_answer

At the topmost position, the speed of the projectile is \mathrm{u\cos\theta}

\mathrm{u \cos \theta=10 \times \cos 30^{\circ}=5 \sqrt{3} \frac{\mathrm{m}}{\mathrm{s}}}

Hence the correct option is 1

Posted by

avinash.dongre

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