Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A ball is thrown from a field with a speed of at an a

A ball is thrown from a field with a speed of 12 \mathrm{~m} / \mathrm{s} at an angle of \mathrm{45^{\circ}} with the horizontal. At what distance will hit the field again? \mathrm{[Take \, \, g=10 \mathrm{~m} / \mathrm{s}^2 ]}

Option: 1

14.4 m


Option: 2

12.5 m


Option: 3

17.4 m


Option: 4

15.5 m


Answers (1)

best_answer

This problem based on projectile motion.

The horizontal range \mathrm{ =\frac{u^2 \sin 2 \theta}{g}}

Now, pit the values \mathrm{u, \theta \, \, \& \, \, g} in above range formula -

\mathrm{ \begin{aligned} \text { Range } & =\frac{(12)^2 \sin 2 \times 45^{\circ}}{10} \\ & =\frac{144 \times \sin 90^{\circ}}{10}=14.4 \times 1 \\ \text { Range } & =14.4 \mathrm{~m} \text { Ans. } \end{aligned} }

Posted by

Devendra Khairwa

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

'PM Modi personally supervising the situation': Centre tells SC in NEET case
anam-khan

NEET Paper Leak Row: NTA informs SC of security overhaul, institutional reforms
anam-khan

Re-NEET 2026 City Intimation Slip LIVE: NTA MBBS admit card soon; direct link, login details, exam date

Latest Question