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  • A block is kept on a floor of a lift at rest . The lift starts descending with an acceleration of <img alt="11 \mathrm{~m} / \mathrm{s}^2" src="https://entrancecorner.oncodecogs.com/gif.latex?11%20

A block is kept on a floor of a lift at rest . The lift starts descending with an acceleration of 11 \mathrm{~m} / \mathrm{s}^2. The displacement of the block during the first 1s after the start is: .

Option: 1

5.5\ m


Option: 2

4.5\ m


Option: 3

5\ m


Option: 4

10\ m


Answers (1)

best_answer

The acceleration of lift is greater than 10 \mathrm{~m} / \mathrm{s}^2 and so block no remain in contact with the lift, it falls under gravity.
h=u t+\frac{1}{2} g t^2=0+\frac{1}{2} \times 10(1)^2=5 \mathrm{~m}

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Riya

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