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A body is fired with velocity of magnitude \sqrt{\mathrm{gR}}<\mathrm{V}<\sqrt{2 \mathrm{gR}} at an angle of 30^{\circ} with the radius vector of earth. If at the highest point the speed of the body is \mathrm{v / 4}, the maximum height attained by the body is equal to

where \mathrm{R=} radius of earth. (Use the appropriate assumptions)

Option: 1

v^2 / 8 \mathrm{~g}


 


Option: 2

\mathrm{R}
 


Option: 3

\sqrt{ } 2 \mathrm{R}
 


Option: 4

None of these


Answers (1)

best_answer

Conservation of angular momentum of the body about \mathrm{O} yields

\mathrm{m v(\sin 30) R=m v^{\prime}(R+h)}

\mathrm{\Rightarrow \frac{\mathrm{v}}{2} \mathrm{R}=\frac{\mathrm{v}}{4}(\mathrm{R}+\mathrm{h})}

\mathrm{\Rightarrow \mathrm{h}=\mathrm{R}}

Hence option 2 is correct.


 

Posted by

Ritika Kankaria

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