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  • A body is imparted a velocity from the surface of the earth. If <img alt="\mathrm{v_0}" src="https://

A body is imparted a velocity \mathrm{v} from the surface of the earth. If \mathrm{v_0} is orbital velocity and \mathrm{v} be the escape velocity then for

(A) \mathrm{\quad v=v_0}, the body follows a circular track around the earth.
(B) \mathrm{\quad v>v_0 but <v_e}, the body follows elliptical path around the earth.
(C) \mathrm{\quad v<v_0}, the body follows elliptical path and returns to surface of earth.
(D) \mathrm{\quad v>v_e}, the body follows hyperbolic path and escapes the gravitational pull of the earth.
 

Option: 1

\mathrm{A}, \mathrm{B}
 


Option: 2

\mathrm{B}, \mathrm{C}
 


Option: 3

\mathrm{A, B, C}
 


Option: 4

\mathrm{\quad A, B, C, D}


Answers (1)

best_answer
  Velocity of Satellite Nature of Path
  \mathrm{V=v_0} Circular path around the earth.
   \mathrm{V< v_0} Elliptical path and body returns to earth.
  \mathrm{V> v_0\: but\: v_e} Elliptical path around the earth and will not escape.
  \mathrm{V=e} Parabolic path and it escapes from the earth.
  \mathrm{V> e} Hyperbolic path and escapes from earth.

Hence option 4 is correct.

Posted by

Suraj Bhandari

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