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  • A body is projected from ground with an angle of   with verti

A body is projected from ground with an angle of  \mathrm{45^{\circ}} with vertical. its velocity after 4 second is 40 m/sec. Find the maximum height attained by body.

Option: 1

40 m


Option: 2

80 m


Option: 3

20 m


Option: 4

zero


Answers (1)

best_answer

\mathrm{\begin{aligned} & R=\frac{u^2 \sin 2 \theta}{g} \\ & R=R_{\text {max }} \\ & \sin 2 \theta=1 \\ & \theta=\frac{\pi }{4} \\ & \operatorname{R} ma x=\frac{u^2}{g}=\frac{1600}{10}=160 \mathrm{~m} \\ &\; \; \; \; \; \; \; \; \; x=\frac{u^2 \sin ^2 \frac{\pi}{4}}{2 g}=\frac{160}{2} \times \frac{1}{2} \\ &\; \; \; \; \; \; \; \; \; \; \; \; =40 \mathrm{~m} \\ & \end{aligned}}

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Rishabh

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