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A body stand on the floor of the moving bus. The bus velocity is \mathrm{e^{i t}} and the mass of the bus is \mathrm{200 \mathrm{~kg}}, mass of the body is \mathrm{20 \mathrm{~kg}}. What will be the acceleration of the bus at time \mathrm{t} ________

Option: 1

\mathrm{i \cos t+\sin t}


Option: 2

0


Option: 3

1


Option: 4

\mathrm{i \cos t-\sin t}


Answers (1)

best_answer

Bus velocity is given by the relation \mathrm{\rightarrow e^{i t}}

\mathrm{\text { Acceleration of the bus }\left(\frac{d v}{d t}\right)=\frac{d}{d t} e^{i t}}

                                  \mathrm{\begin{aligned} \frac{d v}{d t} & =i e^{i t} \\ & =i[\cos t+i \sin t] \end{aligned}}

Now, 

\mathrm{\begin{aligned} \frac{d v}{d t} & =[i \cos t+i \sin t] \\ a=\frac{d v}{d t} & =[i \cos t-\sin t] \text { Ans. } \end{aligned}}\mathrm{\left\{\begin{array}{l} \because e^{i \theta} \\ =\cos \theta+i \sin \theta \\ \dot{i}^2=-1 \\ \text { where } i \text { is the } \\ \text { complex number } \end{array}\right.}                                 

Posted by

Sayak

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